Question

A room is $8$ cm long, $6$ m wide and $10$ m high. Find the length of longest pole that can be placed in the room.

Answer 1

As we know that the length of diagonal is given as-

$d=\sqrt{l^2+b^2+h^2}$

Whereas, $l,b$ and $h$ are the length, breadth and height of the room

Given:-

Length of room $\left(l\right)=8m$

Breadth of room $\left(b\right)=6m$

Height of room $\left(h\right)=10m$

Length of longest pole that can be placed in the room $=$ Length of the diagonal

Therefore,

Length of longest pole that can be placed in the room $=\sqrt{{\left(8\right)}^2+{\left(6\right)}^2+{\left(10\right)}^2}=\sqrt{64+36+100}=10\sqrt{2}m$

Hence the length of longest pole that can be placed in the room is $10\sqrt{2}m$.