A room is heated with a 1500 W electric heater. How much power can be saved if a heat pump with a COP of 2 is used instead ?

0 W

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1500 W

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750 W

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375 W

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Solution

The correct option is C 750 W
Assume the heat pump has to deliver 1500 W as heating effect (HE)

$(C O P)_{H P} = \frac{H E}{W_{i n p u t}}$

$2 = \frac{1500}{W_{i n p u t}}$

$W_{i n p u t} = 750 W$

So the heat pump requires an input of 750 W thus saving the difference,

$W_{s a v e d} = 1500 W - 750 W = 750 W$

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A room is heated with a 1500 W electric heater. How much power can be saved if a heat pump with a COP of 2 is used instead ?

The correct option is C 750 W Assume the heat pump has to deliver 1500 W as heating effect (HE) (COP)HP=HEWinput 2=1500Winput Winput=750 W So the heat pump requires an input of 750 W thus saving the difference, Wsaved=1500W−750 W=750 W