A rope by which a cow is tethered is increased from 16 m to 23 m. How much additional ground does it have now to graze?

Open in App

Solution

Given : length of rope (r) = 16 m

Increased length of rope (R) = 23 m

Hence the additional area cow can graze = $= π R^{2} - π r^{2} = π (R^{2} - r^{2}) = \frac{22}{7} (23^{2} - 16^{2}) = \frac{22}{7} (529 - 256) = \frac{22}{7} \times 273 = 858 m^{2}$

Suggest Corrections

Similar questions

Q. A rope by which a cow is tethered is increased from 16 m to 23 m. How much additional ground does it have now graze?

Q. A rope by which a cow is tethered is increased from

23

m. how much additional ground does it have now to graze?

Q. A rope by which a cow is tethered is increased from 16 m to 23 m. How much additional ground can the cow graze now?

Q. A horse is placed for grazing inside a rectangular field 70 m by 52 m. It is tethered to one corner by a rope 21 m long. On how much area can it graze? How much area is left ungrazed?

A horse is placed for grazing inside a rectangular field $70 m$ by $52 m$ and is tethered to one corner by a rope $21 m$ long. How much area can it graze?

Join BYJU'S Learning Program

A rope by which a cow is tethered is increased from 16 m to 23 m. How much additional ground does it have now to graze?

Given : length of rope (r) = 16 m Increased length of rope (R) = 23 m Hence the additional area cow can graze ==πR2−πr2=π(R2−r2)=227(232−162)=227(529−256)=227×273=858 m2

Given : length of rope (r) = 16 m

Increased length of rope (R) = 23 m

Hence the additional area cow can graze = $= π R^{2} - π r^{2} = π (R^{2} - r^{2}) = \frac{22}{7} (23^{2} - 16^{2}) = \frac{22}{7} (529 - 256) = \frac{22}{7} \times 273 = 858 m^{2}$