Question

A rope can sustain maximum 250 N load. Monkey of mass 30kg is climbing down the rope. How much minimum acceleration monkey must maintain to avoid breakage of the rope?

Answer 1

Given

$Mass=30kg$

$T=250$

So, By using Newton's second law:

$\sum F_y=m{a}_y$

Where f is the force, a is acceleration and m is the mass.

$T-mg=m{a}_y$

$a_y=\frac{T}{m}-g$

$=\frac{250}{30}-10$

$=-\frac{5}{3}m/s^2$

Tus the minimum acdceleration is $-\frac{5}{3}m/s^2$.