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Question

A rope is wound round a hollow cylinder of mass 3 kg and radius 40 cm. If the rope is pulled with a force of 30 N, the angular acceleration of the cylinder will be:

A
10 rads2
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B
15 rads2
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C
20 rads2
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D
25 rads2
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Solution

The correct option is D 25 rads2
Equating the torque about the center of mass we have

F×r=Iα
30×0.4=mr2×α
or
30×0.4=3×0.4×0.4×α

α=25rad/s2.

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