A rope ladder of length L is attached to a balloon of mass M. As the man of mass m climbs the ladder into the balloon basket, the balloon comes down by a vertical distance s. Then the increase in potential energy of man divided by the increase in potential energy of balloon is

\frac{L - s}{s}

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\frac{L}{s}

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\frac{s}{L - s}

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L - s

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Solution

The correct option is A $\frac{L - s}{s}$
Increase in potential energy of a man
$= m g (L - S)$
Increase in potential energy of balloon $= m g . s$
$\frac{m g L - s}{m g s} = \frac{L - s}{s}$

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A rope ladder of length L is attached to a balloon of mass M. As the man of mass m climbs the ladder into the balloon basket, the balloon comes down by a vertical distance s. Then the increase in potential energy of man divided by the increase in potential energy of balloon is

The correct option is A L−ssIncrease in potential energy of a man=mg(L−S)Increase in potential energy of balloon =mg.smgL−smgs=L−ss

The correct option is A $\frac{L - s}{s}$
Increase in potential energy of a man
$= m g (L - S)$
Increase in potential energy of balloon $= m g . s$
$\frac{m g L - s}{m g s} = \frac{L - s}{s}$