A rope of length 10 m and linear density 0.5 kg/m is lying lengthwise on a smooth horizontal floor. It is pulled by a force of 25 N. The tenison in the rope at a point 6 m away from the point of application is :-
A
20 N
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B
15 N
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C
10 N
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D
5 N
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Solution
The correct option is C 10 N acceleration of whole rope ma=25 on 0.5×10×a=25 on a=5.m/s2 Tenstion 6m away will T=(10−6)×0.5×a On T=2×5N on T=10N