CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rope of length 10 m and linear mass density 4 kg/m is lying lengthwise on a horizontal smooth table. One end of the rope is pulled horizontally by a force of 40 N. The tension in the rope at a point 4 m from point of application of force will be

A
40 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
24 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
49 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 24 N

Length of rope =10 m
Density =4 kg/m
Given the floor is smooth
Applied force =40 N
(Ref image)

Let total mass of rope be m.
Then mass of rope m=10×4=40 Kg
The left part has a mass of 6×4=24 Kg, as rope is uniform.

The rope moves as a single piece.
So acceleration of rope is given by
40=4(10)aa=1


T should bring the same acceleration a to 6m length of the wire
T=4(6)aT=24N.

flag
Suggest Corrections
thumbs-up
14
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon