A rope of length 10m and linear mass density 4kg/m is lying lengthwise on a horizontal smooth table. One end of the rope is pulled horizontally by a force of 40N. The tension in the rope at a point 4m from point of application of force will be
A
40N
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B
24N
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C
49N
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D
15N
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Solution
The correct option is B24N
Length of rope =10m Density =4kg/m Given the floor is smooth Applied force =40N (Ref image)
Let total mass of rope be m. Then mass of rope m=10×4=40Kg The left part has a mass of 6×4=24Kg, as rope is uniform.
The rope moves as a single piece. So acceleration of rope is given by 40=4(10)a⇒a=1
T should bring the same acceleration a to 6m length of the wire T=4(6)a⇒T=24N.