A rope tied between two poles and a weight of 40 N is suspended from its middle point. the rope sags by an angle of $1^{0}$ , the tension in the rope will be -

less then 40 N

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equal to 40 N

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greater than 40 N

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none

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Solution

The correct option is C greater than 40 N
REF.Image.
Draw the FBD of rope:
Tension arises due to in own weight.
Apply Lami's theorem from FBD :-
$\frac{m g}{s i n (188^{\circ})} = \frac{T}{s i n (91^{\circ})} \Rightarrow T = \frac{s i n (91^{\circ})}{s i n (178^{\circ})} \times 40 = 1146 N 1146 N > 40 N$
Tension is much greater than 40N.

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A rope tied between two poles and a weight of 40 N is suspended from its middle point. the rope sags by an angle of 10, the tension in the rope will be -

The correct option is C greater than 40 NREF.Image.Draw the FBD of rope:Tension arises due to in own weight.Apply Lami's theorem from FBD :-mgsin(188∘)=Tsin(91∘)⇒T=sin(91∘)sin(178∘)×40=1146N1146N>40NTension is much greater than 40N.

A rope tied between two poles and a weight of 40 N is suspended from its middle point. the rope sags by an angle of $1^{0}$ , the tension in the rope will be -