A rose-coloured compound has the empirical formula $C o C l_{2} .5 N H_{3} . H_{2} O$ . Two moles of this compound react with concentrated sulphuric acid to form HCl(g) and one mole of a new compound with empirical formula $C o_{2} (S O_{4})_{3} .10 N H_{3} .5 H_{2} O$ . When this new compound is dried at room temperature, it loses three moles of water per mol of $C o_{2} (S O_{4})_{3} .10 N H_{3} .5 H_{2} O$ .

What is the formula of the rose-coloured compound?

[C o (N H_{3})_{5} C l] C l_{2} \cdot H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{5} H_{2} O] C l_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C o (N H_{3})_{5} (H_{2} O) \cdot C l_{2}] C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[C o (N H_{3})_{5} H_{2} O] C l_{2}$
As rose colored compound forms two mole of HCl with sulphuric acid so compound is :

$[C o (N H_{3})_{5} H_{2} O] C l_{2} H_{2} S O_{4} - --- \to 2 H C l + [C o (N H_{3})_{5} H_{2} O] S O_{4}$

Therefore, option B is correct.

Suggest Corrections

Similar questions

C H_{2}

42

C o C l_{3} .5 N H_{3}

A g C l

N H_{4}^{+}

0.015

0.0225

A, B

C

C r C l_{3} \cdot 6 H_{2} O (X)

A

(X)

B

C

The empirical formula of an acid is CH₂O. 0.0835 moles of the compound contains 1g of hydrogen. Molecular formula of the compound is ___

Join BYJU'S Learning Program