A rotating fan completes 1200 revolutions every minute. Consider a point on the tip of the blade. Which has a radius of 0.15 m Through what distance does the point move in one revolution? (b) What is the speed of the point? (c) What is its acceleration?

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Solution

According to the question,

$\Rightarrow Ω = 1200 \times 2 π / 60$
$= 40 π r a d / s$
We know that,
$v = r ω$
$= 0.15 \times 40 π$
$= 6 π m / s$
Speed of the point is $6 π m / s$

$A c c e l e r a t i o n = v^{2} / r$
$= (6 π)^{2} / 0.15$
$= 2368.70 m / s^{2}$

Acceleration of point at tip of the blade is 2368.70 m/s^2

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A rotating fan completes 1200 revolutions every minute. Consider a point on the tip of the blade. Which has a radius of 0.15 m Through what distance does the point move in one revolution? (b) What is the speed of the point? (c) What is its acceleration?

According to the question, ⇒Ω=1200×2π/60 =40πrad/sWe know that, v=rω=0.15×40π=6πm/sSpeed of the point is 6πm/sAcceleration=v2/r=(6π)2/0.15=2368.70m/s2Acceleration of point at tip of the blade is 2368.70 m/s^2