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Question

A rotating platform of moment of inertia 100 kg-m2 completes one rotation in 10 seconds A person of mass is 50kg is standing at the center of the platform. If a person moves at a distance of 2m from the center along the radius then find the angular velocity of the platform.

A
π30rad/sec
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B
π60rad/sec
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C
π15rad/sec
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D
π20rad/sec
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Solution

The correct option is B π15rad/sec

Given,

The platform completes one rotation in 10 sec.

ω=2π10=π5

Initially I=100 kgm2

Finally I=100+50×22=300 kgm2

In this process of changing I, no external torque is involved,

Hence,

I1ω1=I2ω2

100\times \dfrac{\pi}{5}=300\omega_2$

ω2=π5×3=π15

Option C is the correct answer

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