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Question

A rought vertical board has an acceleration a, so that a 2 kg block pressing against it does not fall. The coefficient of friction between the block and the board is μ, then


A
μ>ag
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B
μ<ga
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C
μ<ag
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D
μ>ga
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Solution

The correct option is D μ>ga
By the free body diagram of the block,

The wall presses the block and so the reaction force towards left is R and the pseudo force on the block will be towards right as ma

The frictional force (f) here will prevent the block from falling

By the equilibrium condition, balancing the forces in vertical direction we get,

f>mg , where f=μR
μ(R)>mg
μ(ma)>mg
μ>ga

Hence, option D is the correct answer

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