A round seeded plant (R) is dominant over the wrinkled seeded plant (r). What parental genotypes will produce 50% of offspring with RR genotypes and 50 % of offspring with Rr genotypes?

rr and RR

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RR and Rr

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Rr and Rr

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RR and rr

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Solution

The correct option is B
RR and Rr

Since we have a homozygous dominant combination (RR) in the offsprings, both parents should have at least one dominant gene in them to contribute to the offsprings. One-half of the offsprings have one recessive gene. so one of the parents should carry one recessive gene. This logic deduces the parental genotypes to RR and Rr. The Punnet square will look like :
$\begin{matrix} R & R R & R R & R R H o m o z y g o u s & H o m o z y g o u s r & R r & R r H e t e r o z y g o u s & H e t e r o z y g o u s \end{matrix}$

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