A round shaped body is released on an inclined plane. Friction is sufficient for pure rolling, mass of body is m & it is released from a height "h". Then which of the following is correct?

Work done by friction is negative

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At bottom total weight is less than mgh

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Total K.E. on the ground is mgh & ratio of

K E_{t r a n s}

K E_{r o t a t i v e}

depends upon shape of the body

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None of the above

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Solution

The correct option is C Total K.E. on the ground is mgh & ratio of $K E_{t r a n s}$ & $K E_{r o t a t i v e}$ depends upon shape of the body
Since no slipping, $W_{f r i c t i o n} = 0$ & total mechanical energy is conserved. So, it is equal to intial P.E. which is mgh. This distributes between rotational and translational K.E.

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