A round shaped body is released on an inclined plane. Friction is sufficient for pure rolling, mass of body is m & it is released from a height "h". Then which of the following is correct?
A
Work done by friction is negative
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
At bottom total weight is less than mgh
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Total K.E. on the ground is mgh & ratio of KEtrans & KErotative depends upon shape of the body
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Total K.E. on the ground is mgh & ratio of KEtrans & KErotative depends upon shape of the body Since no slipping, Wfriction=0 & total mechanical energy is conserved. So, it is equal to intial P.E. which is mgh. This distributes between rotational and translational K.E.