A round table cover has six equal designs as shown in figure. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of ₹0.35 per $c m^{2}$ . (Use $\sqrt{3} = 1.7$ )

$₹ 157$

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$₹ 195$

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$₹ 167$

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$₹ 200$

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Solution

The correct option is C $₹ 162$

Area of circle $= π \times (28)^{2} = 2464$

The hexagon is made up of 6 equilateral triangles of side 28 cm.

The area of hexagon
$= 6 \times \frac{(28)^{2} \times \sqrt{3}}{4} = 1999.2$

The area of design
$= 2464 - 1999.2 = 464.8 c m^{2}$

Total cost
$= 464.8 \times 0.35$

$= ₹ 162.68$ ~ $₹ 162$

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A round table cover has six equal designs as shown in figure. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of ₹0.35 per cm2 . (Use √3=1.7)

The correct option is C ₹162Area of circle =π×(28)2=2464 The hexagon is made up of 6 equilateral triangles of side 28 cm. The area of hexagon =6×(28)2×√34=1999.2 The area of design =2464−1999.2=464.8 cm2 Total cost =464.8×0.35 =₹162.68 ~ ₹162

A round table cover has six equal designs as shown in figure. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of ₹0.35 per $c m^{2}$ . (Use $\sqrt{3} = 1.7$ )