A rubber ball is dropped from a height of 5m on a plane. On bouncing it rises to 1.8m. The ball loses its velocity on bouncing by a factor of-

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Solution

The correct option is B $2 / 5$
As after first bounce $h_{f} = h e^{2}$ where e is the coefficient of restitution.
$⟹ e^{2} = \frac{1.8}{5} = 0.36$
$⟹ e = 0.6,$
$⟹ v_{f} = e v_{i} = 0.6 v_{i}$
Therefore loss in velocity is $v_{f} - v_{i} = 0.4 v_{i} = \frac{2}{5} v_{i}$

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A rubber ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing, it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of

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A rubber ball is dropped from a height of 5m on a plane. On bouncing it rises to 1.8m. The ball loses its velocity on bouncing by a factor of-

The correct option is B 2/5As after first bounce hf=he2 where e is the coefficient of restitution. ⟹e2=1.85=0.36⟹e=0.6,⟹vf=evi=0.6viTherefore loss in velocity is vf−vi=0.4vi=25vi

The correct option is B $2 / 5$
As after first bounce $h_{f} = h e^{2}$ where e is the coefficient of restitution.
$⟹ e^{2} = \frac{1.8}{5} = 0.36$
$⟹ e = 0.6,$
$⟹ v_{f} = e v_{i} = 0.6 v_{i}$
Therefore loss in velocity is $v_{f} - v_{i} = 0.4 v_{i} = \frac{2}{5} v_{i}$