You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Time Period Independent of Amplitude

A rubber cord...

Question

A rubber cord 10 m is suspended vertically . How much does is stretch under its own weight (density of rubber is $1500 k g m^{- 3}, Y = 5 \times 10^{8} {N m}^{- 2}, g = {m s}^{- 2}$ )

15 \times 10^{- 4} m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.5 \times 10^{- 4} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 \times 10^{- 4} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 \times 10^{- 4} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $15 \times 10^{- 4} m$
The young's modulus is given by $Y = \frac{F / A}{δ l / l}$
so,
$l = \frac{L^{2} d g}{2 Y} = \frac{(10)^{2} \times 1500 \times 10}{2 \times 5 \times 10^{8}} = 15 \times 10^{- 4} m$

Suggest Corrections

Similar questions

A rubber cord 10 m long is suspended vertically. How much does it stretch under its own weight. ( [Density of rubber is $1500 (k g / m^{3}), Y = 5 \times 10^{8} N / m^{2})$

Q. A

10 m e t e r

long thick rubber pipe is suspended from one of its ends. The extension produced in the pipe under its own weight will be :

(Y = 5 \times 10^{6} N / m^{2}

and density of rubber =

1500 k g / m^{3}

)

Q. A rubber cord catapult has cross-sectional area 25 mm

^{2}

and initial length of rubber cord is 10 cm. It is stretched to 5 cm and then released to project a missile of mass 5 g. Taking

Y_{r u b b e r} = 5 \times 10^{8} N m^{- 2}

, velocity of projected missile is:

Q. An Indian rubber cord

L

metre long and area of cross-section

A

meter

^{2}

is suspended vertically. Density of rubber is

ρ k g /

meter

^{3}

and Young's modulus of rubber is

Y

Newton/metre

^{2}

. If the cord extends by

l

metre under its own weight, then extension

l

is:

Q. A rubber cord catapult has cross-sectional area

25 m m^{2}

and initial length of rubber cord is 10 cm It is stretched to 5cm and then released to project a missile of mass 5gm.Taking Y_rubber

5 \times 10^{8} N / m^{2}

, velocity of projected missile is

Join BYJU'S Learning Program

A rubber cord 10 m is suspended vertically . How much does is stretch under its own weight (density of rubber is 1500kgm−3,Y=5×108Nm−2,g=ms−2)

The correct option is A 15×10−4mThe young's modulus is given by Y=F/Aδl/lso,l=L2dg2Y=(10)2×1500×102×5×108=15×10−4m

A rubber cord 10 m is suspended vertically . How much does is stretch under its own weight (density of rubber is $1500 k g m^{- 3}, Y = 5 \times 10^{8} {N m}^{- 2}, g = {m s}^{- 2}$ )

The correct option is A $15 \times 10^{- 4} m$
The young's modulus is given by $Y = \frac{F / A}{δ l / l}$
so,
$l = \frac{L^{2} d g}{2 Y} = \frac{(10)^{2} \times 1500 \times 10}{2 \times 5 \times 10^{8}} = 15 \times 10^{- 4} m$