A rubber cord catapult has cross-sectional area 25mm2 and initial length of rubber cord is 10 cm It is stretched to 5cm and then released to project a missile of mass 5gm.Taking Yrubber5×108N/m2, velocity of projected missile is
A
20 ms−1
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B
100 ms−1
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C
250 ms−1
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D
200 ms−1
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Solution
The correct option is C 250 ms−1 c): Potential energy stored in the rubber cord catapult will be converted into kinetic energy of mass. 12mv2=12YAl2Lv=√YAl2mL √5×108×25×10−6×(5×10−2)25×10−3×10×10−2=250m/s