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Question

A rubber cord of length 10 cm is stretched upto 12 cm. If cross sectional area of cord is 1 mm2, find the velocity of a missile (mass 5g) which is hit upon with this rubber cord. (Yrubber=5×108 N/m2)

A
10 m/s
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B
20 m/s
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C
153 m/s
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D
8 m/s
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Solution

The correct option is B 20 m/s
Δl=1210=2 cmm=5 g, Y=5×108F=YAΔLL
Area of cross section =1 mm2

F=YAΔLLF=5×108×106×210=102 Energy =12×F×ΔL=12mν212×100×2×102=12×5×103v2V2=2×1035V=20 m/s

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