A running man has half the kinetic energy of that of a boy of half of his mass. Ratio of their velocities is:

1 : 1

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3 : 1

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1 : 2

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1 : 4

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Solution

The correct option is C $1 : 2$
$K E_{1} = \frac{1}{2} K E_{2}$
$\frac{1}{2} m v_{1}^{2} = \frac{1}{4} \frac{m}{2} m v_{2}^{2}$
$v_{1} : v_{2} = 1 : 2$

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A running man has half the kinetic energy of that of a boy of half of his mass. Ratio of their velocities is:

The correct option is C 1:2KE1=12KE212mv21=14m2mv22v1:v2=1:2

The correct option is C $1 : 2$
$K E_{1} = \frac{1}{2} K E_{2}$
$\frac{1}{2} m v_{1}^{2} = \frac{1}{4} \frac{m}{2} m v_{2}^{2}$
$v_{1} : v_{2} = 1 : 2$