Question

A $S.H.M.$ has amplitude ${}^{\prime }{a}^{\prime }$ and time period $T$. The maximum velocity will be

• A. $\frac{4a}{T}$
• B. $\frac{2a}{T}$
• C. $2\pi \sqrt{\frac{a}{T}}$
• D. $\frac{2\pi a}{T}$

Answer 1

The correct option is D $\frac{2\pi a}{T}$

As we know $\frac{2\pi }{\omega }=T⟹\omega =\frac{2\pi }{\pi }T$

Maximum velocity$=A\omega =a\left(\frac{2\pi }{T}\right)$