A's salary is $50 %$ higher than $B^{'} s .$ By what per cent is $B^{'} s$ salary lower than $A^{'} s ?$

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Solution

Let B'Salary = 100
then A $= 100 + 100 \times 50 %$
$= 150$
then $150 - 100$
$= 50$
% of B's salary lower then A
$= \frac{50 \times 100}{150}$
$= \frac{100}{3} = 33 \frac{1}{3}$ %

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A's salary is 50% higher than B′s. By what per cent is B′s salary lower than A′s?

Let B'Salary = 100then A =100+100×50%=150then 150−100=50% of B's salary lower then A =50×100150=1003=3313%

A's salary is $50 %$ higher than $B^{'} s .$ By what per cent is $B^{'} s$ salary lower than $A^{'} s ?$

Let B'Salary = 100
then A $= 100 + 100 \times 50 %$
$= 150$
then $150 - 100$
$= 50$
% of B's salary lower then A
$= \frac{50 \times 100}{150}$
$= \frac{100}{3} = 33 \frac{1}{3}$ %