A sample has 0-1 moles of H 2 gas- If 3-011 - 1023 molecules are added to it- what is the final number of moles of H 2 in the sample-

Number of moles = Number of molecules/Avogadro number =3.011× 10^23/6.022×10^23 molecules/mol = 0.5 moles Total number of moles of nbsp; H_2 = 0.1 + 0.5 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Mole Concept

A sample has ...

Question

A sample has 0.1 moles of $H_{2}$ gas. If $3.011 \times 10^{23}$ molecules are added to it, what is the final number of moles of $H_{2}$ in the sample?

Open in App

Solution

$N u m b e r o f m o l e s = \frac{N u m b e r o f m o l e c u l e s}{A v o g a d r o n u m b e r}$
$= \frac{3.011 \times 10^{23}}{6.022 \times 10^{23} m o l e c u l e s / m o l}$
$= 0.5 m o l e s$
Total number of moles of $H_{2} = 0.1 + 0.5 = 0.6 m o l e s$

Suggest Corrections

Similar questions

Q. A sample has 0.1 moles of

H_{2}

gas. If

3.011 \times 10^{23}

molecules are added to it, what is the final number of moles of

H_{2}

in the sample?

Calculate the number of moles of $H_{2}$ in a sample containing $3.011 \times 10^{3} H_{2}$ molecules.

Q. Find the number of moles of

N O_{2}

molecules in a sample containing

3.011 \times 10^{23}

molecules of

N O_{2}

Q. Find the number of moles of

N O_{2}

molecules in a sample containing

3.011 \times 10^{23}

molecules of

N O_{2}

Calculate the number of moles of $H_{2}$ in a sample containing $3.011 \times 10^{3} H_{2}$ molecules.

Join BYJU'S Learning Program

A sample has 0.1 moles of H2 gas. If 3.011×1023 molecules are added to it, what is the final number of moles of H2 in the sample?

Number of moles=Number of moleculesAvogadro number =3.011×10236.022×1023 molecules/mol =0.5 moles Total number of moles of H2=0.1+0.5=0.6 moles

A sample has 0.1 moles of $H_{2}$ gas. If $3.011 \times 10^{23}$ molecules are added to it, what is the final number of moles of $H_{2}$ in the sample?

$N u m b e r o f m o l e s = \frac{N u m b e r o f m o l e c u l e s}{A v o g a d r o n u m b e r}$
$= \frac{3.011 \times 10^{23}}{6.022 \times 10^{23} m o l e c u l e s / m o l}$
$= 0.5 m o l e s$
Total number of moles of $H_{2} = 0.1 + 0.5 = 0.6 m o l e s$