A sample has 0-1 moles of H2 gas- If 3-011-1023 molecules are added to it- what is the final number of moles of H2 in the sample-

Number of moles = Number of molecules/Avogadro number =3.011× 10^23/6.022×10^23 molecules/mol = 0.5 moles Total number of moles of nbsp; H_2 = 0.1 + 0.5 ...

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Standard XII

Chemistry

Mole Concept

A sample has ...

Question

A sample has 0.1 moles of $H_{2}$ gas. If $3.011 \times 10^{23}$ molecules are added to it, what is the final number of moles of $H_{2}$ in the sample?

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Solution

$N u m b e r o f m o l e s = \frac{N u m b e r o f m o l e c u l e s}{A v o g a d r o n u m b e r}$
$= \frac{3.011 \times 10^{23}}{6.022 \times 10^{23} m o l e c u l e s / m o l}$
$= 0.5 m o l e s$
Total number of moles of $H_{2} = 0.1 + 0.5 = 0.6 m o l e s$

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A sample has 0.1 moles of H2 gas. If 3.011×1023 molecules are added to it, what is the final number of moles of H2 in the sample?

Number of moles=Number of moleculesAvogadro number =3.011×10236.022×1023 molecules/mol =0.5 moles Total number of moles of H2=0.1+0.5=0.6 moles

A sample has 0.1 moles of $H_{2}$ gas. If $3.011 \times 10^{23}$ molecules are added to it, what is the final number of moles of $H_{2}$ in the sample?

$N u m b e r o f m o l e s = \frac{N u m b e r o f m o l e c u l e s}{A v o g a d r o n u m b e r}$
$= \frac{3.011 \times 10^{23}}{6.022 \times 10^{23} m o l e c u l e s / m o l}$
$= 0.5 m o l e s$
Total number of moles of $H_{2} = 0.1 + 0.5 = 0.6 m o l e s$