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Organic Compounds

A sample of 0...

Question

A sample of 0.50 gm of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 ml of 0.5 M $H_{2} S O_{4}$ . The residual acid required 60 ml of 0.5 M solution of NaOH for neutralization. Find the percentage composition of nitrogen(X) in the compound.

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Solution

Total miliequivalent (mEq.) of $H_{2} S O_{4}$ taken
$= 50 \times 0.5 \times 2$
$= 50 m E q .$ (since, it is a dibasic acid)
Excess $H_{2} S O_{4} = m E q .$ of $N a O H$
$= 60 \times 0.5 \times 1 = 30 m E q .$ (since, NaOH is a monoacidic base)
mEq. of $H_{2} S O_{4}$ used to neutralise $N H_{3} = (50 - 30) = 20 m E q .$
Percentage of N $= \frac{1.4 \times m E q . o f H_{2} S O_{4} used to neutralise N H_{3}}{Mass of substance}$
$= \frac{1.4 \times 20}{0.5} = 56$ %
Hence, percentage composition of nitrogen in the compound is $56$ .

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