A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process as shown in the figure. The value of $△ H$ for the cycle process will be:

- 12.5 L

atm

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- 5 L

atm

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Zero

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5 L

atm

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Solution

The correct option is A $- 12.5 L$ atm
A sample of $1.0 m o l$
of a monotatomic ideal gas
The value of $Δ H$ for the cycle process will be
$Δ U_{b e} = 1.5 n R (T_{c} - T_{b}) = 1 n R (\frac{10000}{n R} - \frac{5000}{n R}) = 1 n R \frac{5000}{n R} \times \frac{1}{400} = - 12.5 l a t m$

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A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process as shown in the figure. The value of △H for the cycle process will be:

The correct option is A −12.5L atmA sample of 1.0molof a monotatomic ideal gasThe value of ΔH for the cycle process will beΔUbe=1.5nR(Tc−Tb)=1nR(10000nR−5000nR)=1nR5000nR×1400=−12.5latm

A sample of 1.0 mol of a monoatomic ideal gas is taken through a cyclic process as shown in the figure. The value of $△ H$ for the cycle process will be:

The correct option is A $- 12.5 L$ atm
A sample of $1.0 m o l$
of a monotatomic ideal gas
The value of $Δ H$ for the cycle process will be
$Δ U_{b e} = 1.5 n R (T_{c} - T_{b}) = 1 n R (\frac{10000}{n R} - \frac{5000}{n R}) = 1 n R \frac{5000}{n R} \times \frac{1}{400} = - 12.5 l a t m$