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Introduction and Degree of Hydrolysis

A sample of 1...

Question

A sample of 100 ml of 0.10 M acid HA $(K_{a} = 1 \times 10^{- 5})$ is titrated with standard 0.10 M KOH.How many ml of KOH will have to be added when the pH in the titration flask will be 5.00 ?

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100

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Solution

The correct option is D
50

$p H = p K_{a} + l o g \frac{[S a l t]}{[A c i d]}$

5 = 5 + log $\frac{N_{2} V_{2}}{N_{1} V_{1} - N_{2} V_{2}}$

1 = $\frac{0.1 \times V_{2}}{0.1 \times 100 - 0.1 \times V_{2}}$

$\Rightarrow 10 - 0.1 V_{2} = 0.1 V_{2}$

$\Rightarrow V_{2} = 50 m l$

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