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Byju's Answer
Standard IX
Physics
Gamma Decay
A sample of ...
Question
A sample of
40
19
K
contains invariably
40
18
A
r
. This is because
40
19
K
has tendency to undergo:
A
α
-decay
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B
Positronium decay
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C
β
-decay
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D
γ
-decay
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Solution
The correct option is
B
Positronium decay
40
19
K
−
0
1
e
→
40
18
K
Positron is
e
+
. Therefore, $_{19}^{40} has tendency to undergo positronium decay.
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