Question

A sample of a gas has a volume of 10L at $20°\mathrm{C}$. For the volume to become 30L at constant pressure, what will be the Celcius temperature have to be?

Answer 1

It is given in a question,

Pressure - constant

$$\begin{gathered} {\mathrm{V}}_1=10\mathrm{L} \\ {\mathrm{T}}_1=20°\mathrm{C}(273+20)=293 \\ {\mathrm{V}}_2=30\mathrm{L} \\ {\mathrm{T}}_2=? \end{gathered}$$

As the pressure is constant Charle's law is applicable here-

According to Charle's law-

$\frac{{\mathrm{V}}_1}{{\mathrm{T}}_1}=\frac{V_2}{T_2}$

$$\begin{gathered} \frac{10}{293}=\frac{30}{T_2} \\ {\mathrm{T}}_2=\frac{30\times 293}{10} \\ {\mathrm{T}}_2=879\mathrm{K} \\ {\mathrm{T}}_2=(879-273)=606°\mathrm{C} \end{gathered}$$

So, the final temperature in degrees Celcius will be $606°\mathrm{C}$.