A sample of a pure compound contains 9.81gm of Zn, 1.8×1023 atoms of chromium and 0.60 mole of oxygen atoms. What is its simplest formula?
A
ZnCr2O7
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B
ZnCr2O4
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C
ZnCrO4
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D
ZnCrO6
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Solution
The correct option is BZnCr2O4 We know , 9.81gm of Zn=9.8165.3≈0.15mol 1.8×1023atomsofCr=1.8×10236.02×1023≈0.3mol MoleofOatoms=0.60
So from mole ratio Zn:Cr:O=0.15:0.3:0.60=1:2:4
So the simplest formula is ZnCr2O4