A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of $640$ mm. If the vapour pressure of water at that temperature is $40$ mm and mole ratio of $N_{2}$ : $O_{2}$ is $3 : 1$ , the partial pressure of nitrogen in the sample is:

480

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600

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450

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160

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Solution

The correct option is B $450$ mm
Aqueous tension = $40 m m$
Pressure due to $N_{2}$ and $O_{2}$ = $640 - 40 = 600 m m$
Mole fraction of $N_{2} = 3 : 4$
Partial pressure of $N_{2} =$ Mole fraction of $N_{2} \times$ Total pressure
Partial pressure $N_{2}$ is $\frac{3}{4} \times 600 = 450$

Hence, the correct option is $C$

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A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of 640 mm. If the vapour pressure of water at that temperature is 40 mm and the molecular ratio of $N_{2} : O_{2}$ is 3 : 1. Find the partial pressure of nitrogen in the sample.

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A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of 640 mm. If the vapour pressure of water at that temperature is 40 mm and mole ratio of N2 : O2 is 3:1, the partial pressure of nitrogen in the sample is:

The correct option is B 450 mmAqueous tension = 40mmPressure due to N2 and O2 = 640−40=600mmMole fraction of N2=3:4Partial pressure of N2= Mole fraction of N2× Total pressurePartial pressure N2 is 34×600=450Hence, the correct option is C

A sample of air contains nitrogen, oxygen and saturated with water vapour under a total pressure of $640$ mm. If the vapour pressure of water at that temperature is $40$ mm and mole ratio of $N_{2}$ : $O_{2}$ is $3 : 1$ , the partial pressure of nitrogen in the sample is: