A sample of aluminium has a mass of 54.0 g. What is the mass of the same number of magnesium atoms:
(At. wt. Al = 27 u, Mg = 24 u)

12 g

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24 g

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48 g

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96 g

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Solution

The correct option is C $48 g$
$54 g o f A l = \frac{54}{27} m o l o f A l = 2 m o l o f A l$
This sample contains $2 \times N_{A}$ atoms, which will be present in $2 m o l$ of Mg. So the mass of the same number of magnesium atoms will be $24 \times 2 = 48 g$

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Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.

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