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Standard XII

Chemistry

Common Ion Effect

A sample of a...

Question

A sample of an alloy weighing $0.50$ g and containing $90$ % Ag was dissolved in concentrated $H N O_{3}$ . Ag was analysed by Volhard method in which $25$ mL of KCNS was required for complete neutralisation. If the normality of KCNS is $X$ , then find the value of $100 X$ .

16.7

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Solution

The correct option is A 16.7
Weight of $A g = \frac{90 \times 0.5}{100} = 0.45 g$
mEq of $A g$ $=$ mEq of $K C N S$
$\frac{Weight of Ag}{Ew of Ag} \times 1000 =$ Volume in mL $\times N$
$\frac{0.45 \times 1000}{108} = 25 \times N$
$∴ N = 0.167$
$(A g H N O_{3} - --- \to A g N O_{3} K C N S - --- \to A g C N S)$
(mEq of $A g$ $=$ mEq of $A g N O_{3} =$ mEq of $A g C N S$ )

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A sample of an alloy weighing 0.50 g and containing 90% Ag was dissolved in concentrated HNO3. Ag was analysed by Volhard method in which 25 mL of KCNS was required for complete neutralisation. If the normality of KCNS is X, then find the value of 100X.

The correct option is A 16.7Weight of Ag=90×0.5100=0.45 g mEq of Ag = mEq of KCNS Weight of AgEw of Ag×1000= Volume in mL ×N 0.45×1000108=25×N∴N=0.167(AgHNO3−−−−→AgNO3KCNS−−−−→AgCNS)(mEq of Ag = mEq of AgNO3= mEq of AgCNS)

A sample of an alloy weighing $0.50$ g and containing $90$ % Ag was dissolved in concentrated $H N O_{3}$ . Ag was analysed by Volhard method in which $25$ mL of KCNS was required for complete neutralisation. If the normality of KCNS is $X$ , then find the value of $100 X$ .