A sample of an ideal gas is cooled from 450K to 225K. Which of the choices below BEST describes the effect on the average molecular kinetic energy, ¯¯¯¯¯¯¯¯¯KE, and the average molecular velocity, ¯¯¯v?
A
Both ¯¯¯¯¯¯¯¯¯KE and ¯¯¯v are cut in half.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both ¯¯¯¯¯¯¯¯¯KE and ¯¯¯v are reduced by a factor of √2.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
¯¯¯¯¯¯¯¯¯KE is reduced by a factor of √2, while ¯¯¯v is cut in half.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
¯¯¯¯¯¯¯¯¯KE is cut in half while ¯¯¯v is reduced by a factor of √2.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is C¯¯¯¯¯¯¯¯¯KE is cut in half while ¯¯¯v is reduced by a factor of √2. T is reduced from 450K to 225K i.e half times
KE = 32KTKE∝T→V∝1√T
Ans : KE is also cut by half and →V will be reduced by factor of √2