A sample of an ideal gas occupies 20L under a pressure of 0.5 atm. Under isothermal conditions, on increasing its pressure to 1.0 atm, its volume will be:
A
2.5L
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B
20L
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C
5L
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D
10L
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Solution
The correct option is D10L Under isothermal conditions, temperature remains constant.
Using Boyle's law: P1V1=P2V2 0.5×20=1.0×V2 V2=10L