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Question

A sample of CaCO3 has Ca (40%), C (12%), O (48%) by mass. If the law of constant proportions is true then find the mass of Ca in 5 g of CaCO3 obtained from another source.

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Solution

Law of constant proportions states that a given chemical molecule will always contain the same elements in same proportions, irrespective of the source.

Since, it is given that a sample of CaCO3 has 40% Ca in it.

The percentage of Ca in 5 g of sample would be the same as in 100 g of CaCO3
5 g sample CaCO3 will have 40% Ca i.e; 40100×5=2 g

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