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Question

A sample of calcium carbonate (CaCO3) has the following percentage composition: Ca=40%; C=12%; O=48%.
If the law of constant proportions is true, then the weight of calcium in 4g of a sample of calcium carbonate from another source will be:

A
0.016 g
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B
0.16 g
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C
1.6 g
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D
16 g
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Solution

The correct option is B 1.6 g
In 100 g CaCO3, 40 g Ca is present.
In 4 g CaCO3, Let x g Ca be present
x4=40100
x=1.6 g

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