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Standard XII

Chemistry

Laws of Definite Proportions, Multiple Proportions

A sample of c...

Question

A sample of calcium carbonate $(C a C O_{3})$ has the following percentage composition: $C a = 40 %; C = 12 %; O = 48 %$ .
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate from another source will be:

0.016 g

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0.16 g

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1.6 g

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16 g

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Solution

The correct option is B $1.6 g$
In $100$ $g$ $C a C O_{3}$ , $40$ $g$ $C a$ is present.
In $4$ $g$ $C a C O_{3}$ , Let $x$ $g$ $C a$ be present
$\frac{x}{4} = \frac{40}{100}$
$⟹ x = 1.6$ $g$

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Similar questions

Q. A sample of calcium carbonate

(C a C O_{3})

has the following percentage composition

C a = 40 %; C = 12 %; O = 48 %

If the law of constant proportions is true, then the weight of calcium in

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of a sample of calcium carbonate from another source will be

Q. The percentage composition in a sample of

C a C O_{3}

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C a = 40 %; C = 12 %; O = 48 %

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A sample of calcium carbonate (CaCO3) has the following percentage composition: Ca=40%; C=12%; O=48%.If the law of constant proportions is true, then the weight of calcium in 4g of a sample of calcium carbonate from another source will be:

The correct option is B 1.6 gIn 100 g CaCO3, 40 g Ca is present.In 4 g CaCO3, Let x g Ca be presentx4=40100⟹x=1.6 g

A sample of calcium carbonate $(C a C O_{3})$ has the following percentage composition: $C a = 40 %; C = 12 %; O = 48 %$ .
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate from another source will be:

The correct option is B $1.6 g$
In $100$ $g$ $C a C O_{3}$ , $40$ $g$ $C a$ is present.
In $4$ $g$ $C a C O_{3}$ , Let $x$ $g$ $C a$ be present
$\frac{x}{4} = \frac{40}{100}$
$⟹ x = 1.6$ $g$