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Question

A sample of compound is considered to be optically pure:

A
if only one enantiomer is present
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B
if only two enantiomer is present
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C
if the compound is having recimic mixture
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D
none of the above
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Solution

The correct option is A if only one enantiomer is present
If only one enantiomer is present a compound of a sample is considered to be optically pure because it shows some net rotation as it is not having another isomer of it. It does not show any opposite rotation. When a sample consists
of a mixture of enantiomers, the effect of each enantiomer cancels out,
Hence option A is correct.

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