A sample of $C u S O_{4} \cdot 5 H_{2} O$ contains $3.782 g$ of $C u$ . How many grams of oxygen are in this sample? $(C u = 63.5)$

0.952 g

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3.80 g

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4.761 g

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8.576 g

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Solution

The correct option is C $8.576 g$
Molar mass of $C u {S O}_{4} .5 H_{2} O = 1 C u + 1 S + 4 O + 10 H + 5 O = 63.5 + 32.1 + 4 \times 16 + 10 \times 1 + 5 \times 16 = 249.6 g$
Oxygen and copper will be present in $9 : 1$ molar ratio always.
$\frac{144 g o f O}{63.5 g o f C u}$ $= \frac{x g o f O}{3.782 g o f C u}$
Hence, grams of oxygen in this sample $= \frac{144 \times 3.782}{63.5} = 8.576 g r a m$
Hence, the answer is D.

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