Question

A sample of gas at room temperature is placed in an evacuated bulb of volume $0.5d{m}^3$ and is found to exert a pressure of $0.24atm$. The bulb is connected to another evacuated bulb whose volume is $0.63d{m}^3$. What is the new pressure of the gas at room temperature?

Answer 1

Using Boyle's law, at constant temperature,

$P_1{V}_1=P_2{V}_2$

$0.24\times 0.5=1.13\times P_2$

$P_2=0.1062atm$