A sample of gas contracts $200 {c m}^{3}$ by an average of $0.5$ atmosphere while $8.5 J$ heat flows cut into the surroundings. What is the change in energy of the system?
( $1 l i t r e - a t m = 101.3 J$ )

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Solution

$Δ U = Δ q - P d V$
$Δ U = - 8.5 J - 0.5 * 0.2 l i t r e - a t m$
$Δ U = - 8.5 - 0.1 * 101.3 J = - 1.63 J$
since heat is removed by the system,
$Δ U = - 18.63 J$

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A sample of gas contracts 200cm3 by an average of 0.5 atmosphere while 8.5J heat flows cut into the surroundings. What is the change in energy of the system?(1litre−atm=101.3J)

ΔU=Δq−PdVΔU=−8.5J−0.5∗0.2litre−atmΔU=−8.5−0.1∗101.3J=−1.63Jsince heat is removed by the system,ΔU=−18.63J

A sample of gas contracts $200 {c m}^{3}$ by an average of $0.5$ atmosphere while $8.5 J$ heat flows cut into the surroundings. What is the change in energy of the system?
( $1 l i t r e - a t m = 101.3 J$ )

$Δ U = Δ q - P d V$
$Δ U = - 8.5 J - 0.5 * 0.2 l i t r e - a t m$
$Δ U = - 8.5 - 0.1 * 101.3 J = - 1.63 J$
since heat is removed by the system,
$Δ U = - 18.63 J$