Question

A sample of gas occupies $1.50$ L at ${25}^{\circ }$C. If the temperature is raised to ${60}^{\circ }C$, what is the new volume of the gas if pressure remains constant?

• A. $1.2$ L
• B. $1.68$ L
• C. $2.9$ L
• D. $0.86$ L

Answer 1

The correct option is B $1.68$ L

Given:

$V_1=1.50$ L
$T_1=273+25=298$ K
$T_2=60+273=333$ K

Applying Charle's law as pressure is constant,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_2=\frac{V_1{T}_2}{T_1}$

$V_2=\frac{1.5\times 333}{298}$

$V_2=1.68L$

Hence, the correct answer is option $\text{B}$.