wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A sample of H2O2 solution labelled as “28 volume” has density of 265 g/L. Mark the correct option(s) representing concentration of same solution in other units:

A
MH2O2=2.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
%wV=17
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Mole fraction of H2O2=0.2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
mH2O2=13.88
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A MH2O2=2.5
C Mole fraction of H2O2=0.2
D mH2O2=13.88
M=2811.2=2.5

1 L contain 2.5 moles of H2O2

or 2.5×34=85g H2O2

Mass of 1 litre solution = 265g (d=265 g/L)

WH2O=180 g or moles of H2O=10

xH2O2=2.52.5+10=0.2

%wv=2.5×341000×100=8.5

m=2.5180×1000=13.88











flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Limiting Reagent
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon