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Standard XII

Chemistry

Osmotic Pressure

A sample of ...

Question

A sample of $H_{2} S O_{4}$ (density $1.787 g c m^{- 3}$ ) labelled as 86% by weight. What is the normality of acid?

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13.6

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36.36

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15.68

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Solution

The correct option is B 36.36
$.$ 8686g $o f$ H_2SO_4$
$100 g$ of solution
$100 - 86 = 14 g ⟶ H_{2} O$
density= $\frac{86}{1.787} = 48.125 c m^{3} = 48.125 m L$
$n -$ factor of $H_{2} S O_{4} = 2$
$g - e q$ of $H_{2} S O_{4} = \frac{98}{2} = 49$
no. of $g - e q$ of $H_{2} S O_{4} = \frac{86}{49}$ moles
Normality= $\frac{86}{49} \times \frac{1000}{48.125}$
$= 36.469 N$
$= 36.47 N$ (approx)

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A sample of H2SO4 (density 1.787gcm−3) labelled as 86% by weight. What is the normality of acid?

The correct option is B 36.36.8686gofH_2SO_4$100g of solution100−86=14g⟶H2Odensity=861.787=48.125cm3=48.125mLn−factor of H2SO4=2g−eq of H2SO4=982=49no. of g−eq of H2SO4=8649 molesNormality=8649×100048.125=36.469N=36.47N (approx)

A sample of $H_{2} S O_{4}$ (density $1.787 g c m^{- 3}$ ) labelled as 86% by weight. What is the normality of acid?