A sample of hydrazine sulphate $(N_{2} H_{6} S O_{4})$ was dissolved in $100 m L$ of water. $10 m L$ of this solution was reacted with an excess of $F e C l_{3}$ solution and warmed to complete the reaction. Ferrous ion formed was estimated and it required $20 m L$ of $\frac{M}{50} K M n O_{4}$ . Estimate the amount of hydrazine sulphate in one litre of solution.
Reactions: $4 F e^{3 +} + N_{2} H_{4} \to N_{2} + 4 F e^{2 +} + 4 H^{+}$
${M n O_{4}}^{-} + 5 F e^{2 +} + 8 H^{-} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O$ .

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Solution

$20 m L \frac{M}{50} K M n O_{4} = 20 m L \frac{N}{10} K M n O_{4}$
[Equivalent mass of $K M n O_{5} = \frac{M o l e c u l a r m a s s}{5}$ ]
$20 m L \frac{N}{10} K M n O_{4} \equiv 20 m L \frac{N}{10}$ Ferrous ion
$\equiv 20 m L \frac{N}{10} F e C l_{3}$
$\equiv 20 m L \frac{N}{10} N_{2} H_{6} S O_{4}$
Eq. mass $N_{2} H_{6} S O_{4} = \frac{M o l . m a s s}{4} = \frac{130}{4} = 32.5$
[Since, change in $O . N . (N_{2} H_{4} \to N_{2})$ per molecule $= 4$ ]
Amount of hydrazine sulphate in $10 m L$ of solution
$= \frac{1}{10} \times \frac{32.5}{1000} \times 20 = 0.065 g$
Amount of hydrazine sulphate in one litre of solution
$= \frac{0.065}{10} \times 1000 = 6.50 g$ .

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A sample of hydrazine sulphate

(N_{2} H_{6} S O_{4})

was dissolved in

100

mL water.

10

mL of this solution was reacted with excess of

F e C l_{3}

solution and warmed to complete the reaction. Ferrous ions formed was estimated and it required

20

mL of

\frac{M}{50} K M n O_{4}

solution. Estimate the mass of hydrazine sulphate in one litre of solution.

4 F e^{3 +} + N_{2} H_{4} ⟶ N_{2} + 4 F e^{2 +} + 4 H^{+}

M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} ⟶ M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O

A sample of hyhdrazine sulphate $(N_{2} H_{6} S O_{4})$ was dissolved in 100 ml water. 10 ml of this solution was reacted with excess of solution and warmed to complete the reaction. Ferrous ions formed required 20 ml of solution.
Given : $4 F e^{3 +} + N_{2} H_{4} \to N_{2} + F e^{2 +} + 4 H^{+}$
$M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O$