A sample of hydrogen atoms gas contains 100 atoms All the atoms are excited to the seventh state. The total energy released by all the atoms is 480049 Ry( Where Ry = 13 eV) then discuss the following things
a)Maximum energy of the emitted photon will be less then 480049Ry
b)Maximum energy of the emitted photon may be grater than 4849Ry
c)The value of n = 6
d)total number of photon that can be emitted this sample may be less than 600
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Solution
Given that,
Number of atoms, n=100
Energy released by all the atoms is E=480049Ry
Maximum energy of one photon is
480049100=4849
4849Ry=Ry(112−1n′2)
n′=7
∴n=6
Maximum number of photons that can be emitted
is 600.