Question

A sample of hydrogen gas $H_2$ is irradiated by a light of $\lambda =432.25A$ and all hydrogen after atomization gets excited to 3rd orbit. Assuming no energy loss to the surroundings, determine the bond energy of $H_2$ in $kJ/$

Answer 1

Given Radiation energy= $\lambda =432.25R$

Radiant energy= $\frac{1242}{432.25}=2.87kJ/mol$

Given that no loss of energy

$K.E$= Radiation energy- Dissociation energy

$d=2.87-$ dissociation energy

$\Rightarrow$ Dissociation energy= $2.87kJ/mol$